Argon

If the amount of gas in a container is increased, the volume increases. If the amount of gas in a container is decreased, the volume decreases. Gay Lussac’s Law – states that the pressure of a given amount of gas held at constant volume is directly proportional to the Kelvin temperature.

It is also known that volume occupied by 1 mole of gas at NTP is 22.4 L. Substituting P=1 atm, T=293 K, R=0.0821 L atm K−1 mol−1, we get V=24.05 L as the molar volume.

1 Expert Answer V = nRT/P = (1mol)(0.0821 L-atm/K-mol)(273K)/0.987 atm = 22.7 liters or 22.4 liters if you round P to 1 atm.

24.0548 liters

Stoichiometric Calculations Involving Ideal Gases at STP 1 mole of any gas at standard temperature and pressure (273 K and 1 atm) occupies a volume of 22.4 L.

22.4L

The molar volume is the volume occupied by one mole of any gas, at room temperature and pressure. The molar volume is equal to 24 dm 3 (24,000 cm 3). This volume is given in questions that need it.

At standard Temperature and Pressure (STP) the molar volume (Vm) is the volume occupied by one mole of a chemical element or a chemical compound. It can be calculated by dividing the molar mass (M) by mass density (ρ). Molar gas volume is one mole of any gas at a specific temperature and pressure has a fixed volume.

We now know that the volume of 2.155 × 10​​-3 moles of oxygen is about 52.88 cm3. Use this information to calculate the volume of one mole of oxygen. (Your answer may not be exactly this figure, but should be close to it.) At STP, all gases have the same molar volume, which is about 24,000 cm3.