In hydrogen atom, energy of first excited state is-3.4 eV.

stands for singlet corresponding to the plus sign. Thus we have a large effective spin-spin interaction entirely due to electron repulsion. There is a large difference in energy between the singlet and triplet states.

Excited state is defined as the energy state which is higher than the ground state. For the first excited state, n = 2. Hence the value of energy for the first excited energy of hydrogen atom is −3.40eV.

Hence, energy of a possible excited state of hydrogen is -3.4 eV.

The radius of hydrogen atom in the ground state is 0.53 Å. The radius of Li²⁺ ion (atomic number = 3) in a similar state is (a) 0.17 Å

The energy of an electron in the first Bohr orbit of H atom is -13.6eV. The possible energy values (s) of the excited state (s) for electron in bohr orbits of hydrogen is (are) Step by step solution by experts to help you in doubt clearance & scoring excellent marks in exams. =-13.64=-3.4eV in which n=2,3,4 etc.

In the hydrogen atom, the energies corresponding to first, second and third orbits are given by E1 = -13.6 eV, E2 = -3.5eV, E3 = -1.5 eV.

Complete step by step answer: Energy of an electron in the first Bohr orbit of H atom = −13.6eV.

The radius of the second Bohr orbit for hydrogen atom is (Planck’s Const. h=6.6262×10-34 Js, mass of electron = 9.1091×10-31 kg , charge of electron e=1.60210×10-19C, permittivity of vacuum ∈0=8.854185×10-12kg-1m-3A2)

zero.

The He+ ion is just like a hydrogen atom with two units of charge in the nucleus. Since the hydrogenic energy levels depend upon the square of the nuclear charge, the energy of the remaining helium electron should be just 4x(-13.6 eV) = -54.4 eV as observed.

The angular momentum of an electron in a given stationary state can be expressed as me​vr=n2πh​.

The correct option is (b) second line of Balmer series.

An electron makes a transition from orbit n=4 to the orbit n=2 of a hydrogen atom. The wave number of the emitted radiations (R= Rydberg’s constant) will be. Apne doubts clear karein ab Whatsapp par bhi.

When an electron in a hydrogen atom makes a transition from 2nd excited state to ground state, it emits a photon of frequency f. The frequency of photon emitted when an electron of Litt makes a transition from 1st excited state to ground state is :- 243 32.

A hydrogen atom emits a photon corresponding to an electron transition from n=5 to n=1. The recoil speed of hydrogen atom is almost (mass of proton ≈1.6×10-27kg). Step by step solution by experts to help you in doubt clearance & scoring excellent marks in exams. The hydrogen atom before the transition was at rest.

The energy is radiated , when an electron jumps from higher to lower energy orbit and the energy is absorbed, when its jumps from lower to higher energy orbit. It is called Bohr’s frequency condition. Ministry of Finance recruitment 2021, apply for 53 vacancies.

When an electron in hydrogen atom is taken from fourth excited state to ground state (1) Both kinetic energy and potential energy increases (2) Both kinetic energy and potential energy decreases (3) Kinetic energy will increase while potential energy will decrease (4) Kinetic energy will decrease while potential energy …