Answer. Fmin=2.3×10 to the power −28N.

Dielectric constant of a medium is defined as the ratio of forces between two charges placed in vacuum to medium without any change in magnitude of charges and their distance. Therefore, as K decreases there will be an increase in force.

Permittivity is the property to material to offer hindrance to charge to interact with one another hence force and permittivity have inverse relation. Explanation: Permittivity of any given material is the property of material to offer obstruction to the flow of charge or hindrance between charges to interact.

u knw tht,, F= kq1q2 / r2…. nw for a given value of distance, force will be minimum when charge is minimum,,, and minimum value of charge is that carried by a free electron i.e 1.6 * 10 raise to power – 19 c………. so minimum value of electrostatic force is b/w two electrons………..

Minimum possible charge is charge of electron.

=2

Suppose that the two charges are ‘ Let F be the force between them. Then, From the above equation, it is clear that for a given distance, electrostatic force is maximum when they are placed in vacuum.

Greetings! We know that, F=(1/4πε0)(q^1q^2)/r^2. F will be minimum when q1andq2 are minimum i. e. q1=q2=1.6×10−19.

Newtons

3. Find the force between 2C and -1C separated by a distance 1m in air(in newton). Explanation: F = q1q2/(4∏εor2) = -2 X 9/(10-9 X 12) = -18 X 109.

Q1 is the median (the middle) of the lower half of the data, and Q3 is the median (the middle) of the upper half of the data. (3, 5, 7, 8, 9), | (11, 15, 16, 20, 21). Q1 = 7 and Q3 = 16. Step 5: Subtract Q1 from Q3.

The first quartile, denoted by Q1 , is the median of the lower half of the data set. This means that about 25% of the numbers in the data set lie below Q1 and about 75% lie above Q1 . The third quartile, denoted by Q3 , is the median of the upper half of the data set.