Answer Expert Verified The product of two consecutive positive integers is 306. Therefore the numbers are 17 and 18.

10 and 11 are consecutive numbers and when you multiply them, the product will be 110.

Let x be the smallest positive integer. So, (x + 1) is the consecutive positive integer greater than x. Now it is given that the product of two consecutive positive integers is 306. So, first form the quadratic equation.

The two consecutive positive integers whose product is 132 are 11 and 12.

Given two consecutive numbers, one must be even and one must be odd. Since the product of an even number and an odd number is always even, the product of two consecutive numbers (and, in fact, of any number of consecutive numbers) is always even.

Because the next two numbers are consecutive even integers, we can call represent them as x + 2 and x + 4. We are told the sum of x, x+2, and x+4 is equal to 72. This means that the integers are 22, 24, and 26. The question asks us for the product of these numbers, which is 22(24)(26) = 13728.

x2 = 9506. x = √9506 = 97.50. Thus the two numbers should be close to 97.

Numbers that follow each other continuously in the order from smallest to largest are called consecutive numbers. For example: 1, 2, 3, 4, 5, 6, and so on are consecutive numbers.

So, there are four numbers that satisfy the initiaul equation: for x=−9 we have −9 and (−9+1)=−8 , and for x=8 we have 8 and (8+1)=9 . Therefore, −9⋅(−8)=72 and 8⋅9=72 .

2(n−1)! =k⇒n(n+1)=2k. Hence the product of two consecutive integers is divisible by 2. Hence the product of two consecutive integers is even.

Numbers which follow each other in order, without gaps, from smallest to largest. 12, 13, 14 and 15 are consecutive numbers. 22, 24, 26, 28 and 30 are consecutive even numbers.

Thus, the four consecutive even numbers whose sum is equal to 356 are, 82, 84, 86 and 88.

Hence, the three consecutive even numbers are 16, 18 and 20. Want to top your mathematics exam ?