Normality =n× Molarity=2×2=4 N.

So in reference to your question, since sulfuric acid releases 2 protons per molecule, the molarity is half the normality. 0.4 N H2SO4 is 0.2 M H2SO4.

2 N

The formula to calculate this is: Grams of compound needed = (N desired)(equivalent mass)(volume in liters desired). Substituting the above numbers into the equation, we get: grams of compound needed = (1 N)(49)(0.250 liters) = 12.25 grams.

2.5M means 2.5 moles of sulfuric acid per one liter of solution. Convert 2.5 moles to grams. The molar mass of sulfuric acid is 98.09 g/mol….Molarity = Moles Solute / Liter of Solution.

Hence the Normality is equal to 0.2 N. Thus For H2SO4 ( i.e. dibasic ) Normality is 0.2 N and molarity is 0.1M.

With a molar mass of 98.08 grams, a solution containing 98.08 g in 1 liter would have a Molarity of 1 M and a Normality of 2 N.

A 1N solution contains 1 gram-equivalent weight of solute per liter of solution. A 1.0 gram-equivalent weight is the amount of a substance that will combine with or displace 1 atom of hydrogen.

There is a very close relation between molarity and normality. Normality can be described as a multiple of molarity. While Molarity refers to the concentration of a compound or ion in a solution, normality refers to the molar concentration only of the acid component or only of the base component of the solution.

Normality is defined as gram-equivalent of solute dissolved in one litre of solution ,Unit of Morality is N.A solution having normality equals to unity is called normal solution . Normality × equivalent mass=strength of solution in g/L.

1 M H2SO4 solution is more concentrated than 1 N acid solution. Since 1M solution has a greater amount of solute dissolved in it, this solution is more concentrated than 1N solution of the acid.

In 1 molar solution, 1 mole of solute is in 1 litre of solution That means solute and solvent makes 1 litre. While in 1 molal solution 1 mole of solute is dissolved in 1 litre of solvent. So 1 molar solution is more concentrated than 1 molal solution.

Now, we know that the volume of the solution is 1 L, the molarity of the solution is calculated by: Molarity=Moles of the soluteVolume of the solution=55.551=55.55 M. So the Molarity of pure water is 55.55 M.

Normality is a measure of concentration that is equal to the gram equivalent weight of solute per litre of solution. Therefore, 1M HCl is the same as 1N HCl, but when we take sulphuric acid, 1M of sulphuric acids gives 2M of hydrogen ions into the solution.