Since calcium lost two electrons, it has 20 protons, but only 18 electrons. This makes calcium a positive ion with a charge of 2+.

Calcium nitride is the inorganic compound with the chemical formula Ca3N2.

Calcium nitride (Ca3N2)

Calcium nitride is a red-brown, crystalline solid made up of calcium and nitrogen. Its chemical formula is Ca3N2 .

Calcium is a metal, so its formula will simply be Ca . Nitrogen is a diatomic molecular compound, making it N2 . Since calcium nitride is an ionic compound, by evaluating its constituent ions we can determine its formula. The calcium ion is a 2+ ion, or Ca2+ .

Calcium is also in Group 2. It has two electrons in its outer shell. When these electrons are lost, a calcium ion, Ca 2+, is formed. A calcium ion has the same electronic structure as an argon atom (Ar).

Would you expect a calcium ion to be bigger, smaller or the same size as a calcium atom? Calcuim is in group two which means when it forms an ion it will donate its two outer elections, this means a calcium ion will be smaller as it has one less shell of electrons.

In the case of the calcium ion, we have a calcium element with a positive charge of 2. Positively charged atoms are called cations. This simply means that the element calcium needs two more electrons to equal the number of protons that it has; this balances the charge, or makes it zero.

The radius of a calcium ion is smaller than the radius of a calcium atom because the calcium ion contains the same nuclear charge and They have two valence electrons, and the form ions with a 2+ charge. They have two valence electrons, and the form ions with a 2- charge.

So in the question, it is asked why calcium ions possess a smaller ionic radius than the potassium ion. For solving this question we should know the atomic numbers of the elements of the ions given. Ca loses 2 electrons from the electronic configuration hence there will be only 18 electrons in them.

For a) the neutral Ca atom has a larger radius than the Ca2+ ion. This is because the loss of electrons reduces the shielding effect between the electrons and the nucleus, so the attraction of the nucleus for the electrons is greater, reducing the radius.

Calcium (atomic # = 20) has a bigger atomic radius than Sodium (atomic # = 11) because it has a greater number of electrons, which are also found farther from the nucleus because of the orbital in which calcium’s valence electrons are found.

Fe2+ is greater in size than Fe3+. This is because the outermost electron in the Fe2+ ion is pulled off to form Fe3+ ion. As the electrons are removed, it reduces the repulsion increasing nuclear charge experienced by each of the other d electrons and decreases the size of the ion.

Explain your answer. mg2+ would be the smaller ion this is because each ion has the same number of electrons however mg2+ has a greater number of protons and therefore is more charge dense and the outer electrons feel a greater pull from the nucleus.

(i) The sodium ion (Na+) is larger than the magnesium ion (Mg2+) due to two effects.

Na+ has smaller size than F- because both Na+ and F- have equal number of electrons i.e.10 . After losing an electron Na will have less electron cloud and more effective nuclear charge whereas F after gaining an electron will have less effective nuclear charge than the parent atom so the size increases .

Ba has an atomic number of 56 while K’s is 19. The atomic numbers are the number of protons in their nucleii. Thus Ba has almost 3 times as many and thus exerts a much more powerful attractive force on all its electrons. This draws them in closer to its nucleus, which is why it has a smaller atomic radius.