if (log n) / (log 3) is integral then n is a power of 3….If input values are evenly distributed over the range of UInt32 , here are the probabilities associated with this algorithm:

Any number raised to the power of one equals the number itself.

The exponent of the number 2, 10, also called index or power, denotes how many times to multiply the base (2). 2 to the power of 10 = 210 = 1024.

Suppose we have a number n. So if the number is like n = 27, that is the power of 3, the result will be true, if n = 15, it will be false. …

Power of Two – LeetCode. Given an integer n , return true if it is a power of two. Otherwise, return false . An integer n is a power of two, if there exists an integer x such that n == 2x .

1. Return in or before the first optimizing line: 66% of the time.
2. Return in or before the second optimizing line: 89% of the time.

Method-2: Keep dividing by 2 Keep dividing the number by two, i.e, do n = n/2 iteratively until n becomes 1. In any iteration, if n%2 becomes non-zero and n is not 1 then n is not a power of 2. If n becomes 1 then it is a power of 2.

Power of Three – LeetCode. Given an integer n , return true if it is a power of three. Otherwise, return false . An integer n is a power of three, if there exists an integer x such that n == 3x .

Number is a power of 10 if it’s equal to 10, 100, 1000 etc. 1 is also 0-th power of 10. Other numbers like 2, 3, 11, 12 etc. are not powers of 10.