For oxidizing agents and reducing agents, the n factor is equal to the number of electrons transferred by one mole of the oxidizing agent or reducing agent. Potassium dichromate is converted to chromium chloride. So, 1mole of HCl loses 614electrons. Thus, the n factor of HCl is 37.

Sulphuric Acid (H2SO4) is used in the redox titration process because it provides the H(+) ions necessary for the reaction to occur more quickly whilst the sulphate(-) ions barely react during the reaction. Therefore, sulfuric acid is added to make the solution acidic.

Why we don’t use HCl in redox titration: HCl is a terrible reductant. It only shows the ability to reduce when it’s concentrated and reacts with strong oxidizer (e.g. manganese dioxide). Titration only works with dilute solutions.

The reaction of KMnO4 and HCl results in__________.

So N factor is 73.

The n factor of bacl2 will be 2. The n factor of a molecule is defined as the total sum of positive charges in the molecule.

Answer: So, the oxidation number of carbon changes from +3 to +4. As, there are two carbon atoms, the net change in oxidation number is +2 and adding to this the increase in oxidation state of iron, the final increase in oxidation number is +3. Hence, the n-factor of is 3.

n factor for sodium hydroxide is 1. Since there is +1 charge on Na and -1 charge on OH.

The n-factor is 8+4=12.

How to calculate the n factor of Fe2O3 in this reaction Fe2O3+3C=2Fe+3CO. Dear Student, The n-factor is the number of moles of electrons gained or lost by one mole of salt. Therefore the n factor is 3.

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Thus, the oxidation state of Cu in CuSO4 is +2. Thus, the oxidation state of Cu in Cu2I2 is +1. Thus, the n-factor for CuSO4 is 2. Thus, the equivalent mass of CuSO4 in the reaction CuSO4+KI→Product is 124.

It mean one third on Fe mole is enough to combine with 8−gram of O2 Therefore, the equivalent weight of iron in Fe2O3 =355. 8=18. 6 g.

So, the molecular weight of ferrous sulphate is 151.8. -Equivalent weight of ferrous sulphate = molecular weight of ferrous sulphate/ involved electron. So, equivalent weight of ferrous sulphate which is present as reductant is 151.8 which is equal to the molecular weight of ferrous sulphate.

The equivalent weight of aluminium chloride salt= 133.34 / 3 = 44.44.

Therefore, the equivalent weight of $F{e_3}{O_4}$ is $/dfrac{M}{1}$.

So, Equivalent weight of Fe =3856=21.

In FeO, valency of iron is 2 and in Fe2O3, valency of iron is 3. Hence in Fe3O4, one iron atom has a valency 2 while two iron atoms have valency of 3.

Iron (Fe) has an atomic number of 26, i.e. has 26 electrons. The energy of 4s and 3d orbital is similar (4s has slightly higher energy). Also note that the 3d orbital has 1 electron pair, rest of the electrons are unpaired. When iron loses the 2 4s electrons, it attains a valency of +2.

Description. Ferrosoferric oxide is an iron oxide. ChEBI. Iron (II,III) oxide (Fe3O4). It is a black ore of IRON that forms opaque crystals and exerts strong magnetism.

Fe3O4 is formed with the combination of FeO and Fe2O3 i.e. ferrous oxide and ferric oxide.

How is Fe2O3 formed? Iron (III) oxide, or ferric oxide, is the product that is formed when iron undergoes oxidation. This can be prepared in the laboratory by electrolyzing a sodium bicarbonate solution, an inert electrolyte, with an iron anode. The resulting hydrated iron(III) oxide, is dehydrated at around 200 °C.