Converting from moles to volume (liters): Multiply your mole value by the molar volume constant, 22.4L. Converting from particles (atoms, molecules, or formula units) to moles: Divide your particle value by Avogadro’s number, 6.02×1023. Remember to use parentheses on your calculator!

1mol O2 occupies 22.4L of volume at STP.

First question: If there is no net flow of solute into or out of the volume during change in volume of the solvent, the number of moles of solute remains the same. However, the concentration changes inversely with volume.

1. First you must calculate the number of moles in this solution, by rearranging the equation. No. Moles (mol) = Molarity (M) x Volume (L) = 0.5 x 2. = 1 mol.
2. For NaCl, the molar mass is 58.44 g/mol. Now we can use the rearranged equation. Mass (g) = No. Moles (mol) x Molar Mass (g/mol) = 1 x 58.44. = 58.44 g.

Molarity (M) is defined as the number of moles of solute (n) divided by the volume (V) of the solution in liters. It is important to note that the molarity is defined as moles of solute per liter of solution, not moles of solute per liter of solvent.

Molarity can be used to calculate the volume of solvent or the amount of solute. The relationship between two solutions with the same amount of moles of solute can be represented by the formula c1V1 = c2V2, where c is concentration and V is volume.

When the base neutralizes the acid, the number of moles of H+ = the number of moles of OH-. Therefore, the number of moles of H+ = 0.0125 moles. Every mole of HCl will produce one mole of H+; therefore, the number of moles of HCl = number of moles of H+. The concentration of the HCl is 0.25 M.

Let us assume that we want to prepare 1 L of 1 mol/L HCl.

1. Calculate the moles of HCl needed. Moles of HCl=1L HCl ×1 mol HCl / 1L HCl=1 mol HCl.
2. Calculate the mass of HCl Needed. Mass of HCl=1mol HCl× 36.46 g HC / l1mol HCl=36.46 g HCl.
3. Calculate the mass of solution required.
4. Calculate the volume of solution required.

A 1:1 mole ratio basically means that the reaction consumes equal numbers of moles of sodium hydroxide and of hydrochloric acid. In other words, for every 1 mole of sodium hydroxide that takes part in the reaction, you need 1 mole of hydrochloric acid to neutralize it.

So, the solution will be neutralized when the number of moles of H+ equals the number of moles of OH-.

1. Step 1: Calculate the number of moles of OH-. Molarity = moles/volume. moles = Molarity x Volume.
2. Step 2: Calculate the Volume of HCl needed. Molarity = moles/volume. Volume = moles/Molarity.